Question

Find the probability of getting an odd number in a single throw of a die.

Answer 1

Total possible outcomes on throwing a die$=\{1,2,3,4,5,6\}$
$\therefore$ Total number of cases $=6$
Favourable cases $=\{1,3,5\}$
Number of favourable cases $=3$
Probability $P\left(E\right)=\frac{\text{Number of favourable cases}}{\text{Total number of cases}}$
$P\left(E\right)=\frac{3}{6}$
$P\left(E\right)=\frac{1}{2}$