Question

Find the probability of scoring a total of more than 7, when two dice are thrown

• A. $5/12$
• B. $5/18$
• C. $5/6$
• D. $5/24$

Answer 1

Answer: (A)

$5/12$

Given, Two dice are thrown.
The total no.of outcomes when two dice are thrown,N=$6\ast 6=36$
The total set of outcomes for which sum of the no.'s on two dice is greater than 7,$X$={$(2,6),(3,6),(3,5),(4,6),(4,5),(4,4),(5,6),(5,5),(5,4),(5,3),(6,6),(6,5),(6,4),(6,3),(6,2)$}
$\Rightarrow n\left(X\right)=15$
$\therefore$ The required probability=$\frac{n\left(X\right)}{N}=\frac{15}{36}=\frac{5}{12}$