Question

Find the probability that person has either $1$ car or more than $2$ cars.

• A. $\frac{1}{2}$
• B. $\frac{3}{8}$
• C. $\frac{5}{8}$
• D. $\frac{1}{8}$

Answer 1

Answer: (C)

$\frac{5}{8}$

Total number of persons $=2000$

Number of persons having $1car=1200$

Number of persons having more than $2cars=50$

$P\left(A\right)=\frac{Numberoffavorableoutcomes}{TotalNumberofpossibleoutcomes}$

$\therefore$ probability that person has either 1 car or more than 2 cars:

$P\left(A\right)=\frac{1200}{2000}+\frac{50}{2000}$

$\therefore P\left(A\right)=\frac{1250}{2000}=\frac{5}{8}$

Hence, option $C$ is correct.