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Question
Find the probability that the birth days of six different persons will fall in exactly true calender months.
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Solution
No of ways of choosing 2 months from 12= C¹²₂
no of possible months= 12⁶
applying combination
= ( C₂¹² . 2⁶−2 )/12⁶ ( 2 is subtracted as the case involving all having birthdays in the same month )
= 341/12⁵
no of possible months= 12⁶
applying combination
= ( C₂¹² . 2⁶−2 )/12⁶ ( 2 is subtracted as the case involving all having birthdays in the same month )
= 341/12⁵
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