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Question

Find the product.
(3+2)(2+3)(32)(23)

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Solution

We have,
=(3+2)(2+3)(32)(23)
=(3+2)(32)(2+3)(23)

We know that,
a2b2=(a+b)(ab)

Therefore,
=(92)(43)
=7×1
=7

Hence, the product is 7.

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