Question

Find the product:
(3p² + q²) × (2p² − 3q²)

Answer 1

By horizontal method:

$$\begin{gathered} (3p^2+q^2)\times (2p^2-3q^2) \\ =3p^2(2p^2-3q^2)+q^2(2p^2-3q^2) \\ =6p^4-9p^2{q}^2+2p^2{q}^2-3q^4 \\ i.e6p^4-7p^2{q}^2-3q^4 \end{gathered}$$