Find the product:
$(3 x + 21 y) (4 x - 28 y)$

$12 x^{2} - 588 y^{2}$

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$x^{2} - 49 y^{2}$

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$12 x^{2} - 588 y^{2} - 48 x y$

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$7 x^{2} - 49 y^{2} - 48 x y$

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Solution

The correct option is A
$12 x^{2} - 588 y^{2}$

$(3 x + 21 y) (4 x - 28 y)$

$= 3 (x + 7 y) .4 (x - 7 y)$

$= 12 (x + 7 y) (x - 7 y)$

$= 12 (x^{2} - (7 y)^{2})$

$= 12 (x^{2} - 49 y^{2})$

$= 12 x^{2} - 588 y^{2}$

Suggest Corrections

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