Find the product $- 3 y (x y + y^{2})$ and find its value at $x = 4$ and $y = 5$

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Solution

We simply substitute $x = 4, y = 5$ in the given product $- 3 y (x y + y^{2})$ as follows:

$- 3 y (x y + y^{2}) = - (3 \times 5) ((4 \times 5) + 5^{2}) = - 15 (20 + 25) = - 15 \times 45 = - 675$

Hence, $- 3 y (x y + y^{2}) = - 675$ when $x = 4, y = 5$ .

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