Find the product $- 3 y (x y + y^{2}) and find its value for x = 4 a n d y = 5.$

Open in App

Solution

$- 3 y (x y + y^{2}) = - 3 y \times x y - 3 y \times y^{2} = - 3 x y^{2} - 3 y^{2 + 1} = - 3 x y^{2} - 3 y^{3} I f x = 4, y = 5, t h e n = - 3 \times 4 (5)^{2} - 3 (5)^{3} = - 12 \times 25 - 3 \times 125 = - 300 - 375 = - 675$

Suggest Corrections

Similar questions

¯ ¯ ¯ x

¯ ¯ ¯ y

[2 ¯ ¯ ¯ x + 3 ¯ ¯ ¯ y ¯ ¯ ¯ x ¯ ¯ ¯ y] =

x y (x^{2} - 2 x + y^{2})

x = - 1, y = 1

4 x y (x - y) - 6 x^{2} (y - y^{2}) - 3 y^{2} (2 x^{2} - x) + 2 x y (x - y)

x = 5

y = 13

Find the product (x $^{2}$ -3xy+2y $^{2}$ ) (2x-3y) and also find its value when x = 4 and y = -3.

x y = 5

(x + y) = 36

x^{2} + y^{2}

Join BYJU'S Learning Program