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Question

Find the product.

(i) (52x)(3+x) (ii) (x+7y)(7xy)

(iii) (a2+b)(a+b2) (iv) (p2q2)(2p+q)

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Solution

(i)Given (52x)(3+x)=5(3+x)2x(3+x)=15+5x-6x-2x^2\therefore (5 − 2x)(3 + x)=-2x^2-x+15$

(ii) Given (x+7y)(7xy)=x(7xy)+7y(7xy)
=7x2xy+49xy7y2
(x+7y)(7xy)=7x2+48xy7y2

(iii) Given (a2+b)(a+b2)=a2(a+b2)+b(a+b2)
(a2+b)(a+b2)=a3+a2b2+ab+b3

(iv) Given (p2q2)(2p+q)=p2(2p+q)q2(2p+q)
(p2q2)(2p+q)=2p3+p2q2pq2q3


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