We have,
(3+√2)(2+√3)(3−√2)(2−√3)
=(3+√2)(3−√2)(2+√3)(2−√3)
=[32−(√2)2][22−(√3)2]
=(9−2)(4−3)
=7
Hence, this is the required solution.
Find the sum to n terms of the series 312×22+522×33+732×42...... is