Find the product of $(2 a^{2} + 9) (2 a^{2} + 5) .$

Open in App

Solution

Given: $(2 a^{2} + 9) (2 a^{2} + 5)$
This is in the form of $(x + a) (x + b)$ where $x = 2 a^{2}, a = 9 a n d b = 5.$

We know that,
$(x + a) (x + b) = x^{2} + (a + b) x + a b$
$(2 a^{2} + 9) (2 a^{2} + 5) = (2 a^{2})^{2} + (9 + 5) \times 2 a^{2} + 9 \times 5$
$= 4 a^{4} + 14 \times 2 a^{2} + 45$
$= 4 a^{4} + 28 a^{2} + 45$

Suggest Corrections

Similar questions

(x + a) (x + b) = x^{2} + (a + b) x + a b

(2 a^{2} + 9) (2 a^{2} + 5)

(x + a) (x + b) = x^{2} + (a + b) x + a b

(x + 3) (x + 7)

(4 x + 5) (4 x + 1)

(4 x - 5) (4 x - 1)

(4 x + 5) (4 x - 1)

(2 x + 5 y) (2 x + 3 y)

(2 a^{2} + 9) (2 a^{2} + 5)

(x y z - 4) (x y z - 2)

Use the identity $(x + a) (x + b) = x^{2} + (a + b) x + a b$ to find the product of $({2 a}^{2} + 9) ({2 a}^{2} + 5)$ .

(x + a) (x + b) = x^{2} + (a + b) x + a b

(2 a^{2} + 9) (2 a^{2} + 5)

(x + a) (x + b) = x^{2} + (a + b) x + a b

(2 x + 5 y) (2 x + 3 y)

(2 a^{2} + 9) (2 a^{2} + 5)

Join BYJU'S Learning Program