Question

Find the product of $3\times \sqrt[3]{332}\times 3\times \sqrt{4}$

• A. $36\sqrt[3]{34}$
• B. $24\sqrt[3]{34}$
• C. $32\sqrt[3]{34}$
• D. $36\sqrt[3]{33}$

Answer 1

Answer: (A)

$36\sqrt[3]{34}$

$3\times \sqrt[3]{332}\times 3\times \sqrt{4}$

$=3^{\frac{1\times 3}{3}}\times {32}^{\frac{1}{3}}\times 3^{\frac{1\times 3}{3}}\times 2^{\frac{1\times 3}{3}}$

$={27}^{\frac{1}{3}}\times {32}^{\frac{1}{3}}\times {27}^{\frac{1}{3}}\times 8^{\frac{1}{3}}$

$=\sqrt[3]{3186624}=\sqrt[3]{3{36}^3\times 4}=36\sqrt[3]{34}$