Find the product of $5 m^{2} n, - 3 m n p$ and $- 5 n^{2} p$ .

75 m^{3} n^{3} p^{2}

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75 m^{3} n^{4} p^{2}

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75 m n^{3} p^{3}

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75 m^{3} n p^{2}

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Solution

The correct option is B $75 m^{3} n^{4} p^{2}$
$5 m^{2} n \times (- 3 m n p) \times (- 5 n^{2} p)$
= $75 m^{(2 + 1)} n^{(1 + 1 + 2)} p^{(1 + 1)}$
= $75 m^{3} n^{4} p^{2}$

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Similar questions

5 m^{2} n, - 3 m n p a n d - 5 n^{2} p

5 m^{2} n, - 3 m n p

- 5 n^{2} p

Find the product of $5 m^{2} n, - 3 m n p$ and $- 5 n^{2} p$ .

5 m^{2} n, - 3 m n p

- 5 n^{2} p

m = 3

n = 2

- 2 m^{3} - 3 n^{2} + 5 m^{2} n

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