Find the product of all prime numbers between 1 and 20
Option (b)
Go by elimination. Option a is eliminated because the product of prime numbers 2,5 is 2×5=10, which should yield one zero
As 3 is a factor of the product, check which of the remaining options are a multiple of 3. only option (b) and option (e) are both factors of 3.
Checking for 7 and 13.Sum of triplets at odd places-sum of triplets at even places=0 in option (b). Hence, this is the answer.