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B
C6H5CH2−OH,CH3CH2−I,I−CH2CH2−OH
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C
I−CH2CH2−I,C6H5CH2−I,CH3CH2−OH
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D
HO−CH2CH2−OH,C6H5CH2−I,CH3CH2−OH
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Solution
The correct option is BOH−CH2CH2OH,C6H5CH2−I,CH3CH2−I Presence of excess of HI favours SN1 mechanism. So, formation of products is controlled by the stability of the carbocation resulting in the cleavage of C−O bond in protonated ether.
Since C6H5−CH+2 is more stable due to resonance. (SN1 mechanism)
Thus the product for given equation are C6H5CH2I,CH3CH2I,HOCH2−CH2OH