Question

Find the product of $3\sqrt{2}-2\sqrt{3}$ and its conjugate

• A. $2$
• B. $6$
• C. $-8$
• D. $12$

Answer 1

The correct option is B $6$

The conjugate of $3\sqrt{2}-2\sqrt{3}$ is $3\sqrt{2}+2\sqrt{3}$
$(3\sqrt{2}-2\sqrt{3})(3\sqrt{2}+2\sqrt{3})=9\times 2-4\times 3=18-12=6$