Question

Find the product of $\frac{4}{6}ab$ and $\frac{-3}{10}{x}^{2}y$.

• A. $\frac{-1}{5}abxy$
• B. $\frac{-1}{5}ab{x}^{2}y$
• C. $\frac{1}{5}abxy$
  
• D. $\frac{1}{5}ab{x}^{2}y$
  

Answer 1

The correct option is B

$\frac{-1}{5}ab{x}^{2}y$

$\left(\frac{4}{6}ab\right)\left(\frac{-3}{10}{x}^{2}y\right)$

$=\left(\frac{4}{6}\right)\left(\frac{-3}{10}\right)ab{x}^{2}y$

$=\frac{-12}{60}ab{x}^{2}y$

$=\frac{-1}{5}ab{x}^{2}y$