Question

Find the product of $-\frac{9}{16}{a}^3{b}^{2}and3\frac{1}{5}ab$.

Answer 1

Given that: Find the product of $-\frac{9}{16}{a}^3{b}^{2}and3\frac{1}{5}ab$.

Product of two monomials $=$ (Product of their numerical coefficients) $\times$ (Product of their literal coefficients)

$$\begin{gathered} (-\frac{9}{16}{a}^3{b}^2)\left(3\frac{1}{5}ab\right)=(-\frac{9}{16}\times 3\frac{1}{5})\times (a^3{b}^2\times ab) \\ =(-\frac{9}{16}\times \frac{16}{5})\times \left(a^4{b}^3\right) \\ =-\frac{9}{5}{a}^4{b}^3 \end{gathered}$$.

Therefore, we get $-\frac{9}{5}{a}^4{b}^3$