Find the product of given monomials:
$m, 4 m, 3 m^{2}$ and $- 6 m^{2}$

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Solution

Given monomials are $m, 4 m, 3 m^{2}, - 6 m^{2}$
Their product is $m \times 4 m \times 3 m^{2} \times (- 6 m^{2})$
$= 1 \times 4 \times 3 \times (- 6) \times m^{1 + 1 + 2 + 2}$
$= - 72 m^{6}$

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