Question

Find the product of LCM and HCF of the following pair of integers

510 and 92

Answer 1

Prime factorisation of $510=2\times 3\times 5\times 17$
Prime factorisation of $92=2\times 2\times 23$
Hence, LCM of $510,92=2\times 3\times 5\times 17\times 2\times 23=23460$
And HCF of $510,92=2$
Now, LCM $\times$ HCF $=23460\times 2=46920$
Also, $510\times 92=46920$
i.e., HCF $\times$ LCM $=$ Product of the two numbers