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Question

Find the product of (103pq3)×(65p3q)

A
p4q4
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B
4p4q4
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C
4p2q4
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D
4q4p5
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Solution

The correct option is B 4p4q4
(103pq3)×(65p3q)
=2pq3×2p3q
=4p4q4

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