Find the product of roots of the quadratic equation $2 x^{2} + 24 x + 36 = 0$

$18$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$- 24$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{3}{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$\frac{- 2}{3}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$18$

Product of roots of a quadratic equation of the form $a x^{2} + b x + c = 0$ is $\frac{c}{a}$ . The value of a = 2, b = 24, c = 36.
Therefore, product of roots of the equation $2 x^{2} + 24 x + 36 = 0$ is $\frac{c}{a} = \frac{36}{2} = 18$ .

Suggest Corrections

Similar questions

x^{2} + 24 x + 36 = 0

The sum of roots of the equation 2 $x^{2}$ - 3+ $\sqrt{2}$ = 0

Find the roots of the following quadratic equation by factorisation method.
$2 x^{2} + \frac{5}{3} x - 2 = 0$

Find the roots of the following equation applying quadratic formula.
$4 x^{2} + 4 \sqrt{3} x + 3 = 0$

Which of the following is one of the roots of the quadratic equation ${2 x}^{2} - 7 x + 3 = 0$ ?

Join BYJU'S Learning Program