Find the product of the following pairs:
$- 5 p^{2}, - 2 p$

10 p^{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

10 p^{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20 p^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $10 p^{3}$
We multiply the given polynomials $- 5 p^{2}$ and $- 2 p$ as shown below:

$(- 5 p^{2}) \times (- 2 p) = (- 5 \times p \times p) \times (- 2 p) = (- 5 \times - 2) \times (p \times p \times p) = 10 \times p^{3} = 10 p^{3}$

Hence, the product of $- 5 p^{2}$ and $- 2 p$ is $10 p^{3}$ .

Suggest Corrections

Similar questions

(i)

6, 7 k

(i i)

- 3 l, - 2 m

(i i i)

- 5 t^{2}, - 3 t^{2}

(i v)

- 6 n, - 3 m

(v)

- 5 p^{2}, - 2 p

- 2 p, - 3 q, - 5 p^{2}

(p^{2} - 5) (p^{2} - 3)

5 p^{2} + 25 p q + 4 q^{2}

2 p^{2} - 2 p q + 3 q^{2}

10 p^{4} + 40 p^{3} q - 27 p^{2} q^{2} + 67 p q^{3} - 12 q^{4}

- 5 t^{2}, - 3 t^{2}

Join BYJU'S Learning Program