Find the product of the following pairs of monomials:
$- 4 p, 7 p$

- 28 p^{2}

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14 p^{2}

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- 12 p^{2}

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16 p^{2}

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Solution

The correct option is A $- 28 p^{2}$
After multiplying the above two monomials we get
$- 4 p \times 7 p = (- 4 \times 7) \times (p \times p)$
$= - 28 p^{2}$
$= - 28 p^{2}$

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