Find the product of the following pairs of monomials.
$4 p, 7 p q$

p^{2} q

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28 p^{2} q

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28 p q

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28 p^{2}

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Solution

The correct option is B $28 p^{2} q$
$4 p, 7 p q$
The product of the monomial pair is,
$= 4 \times p \times 7 \times p \times q$
$= (4 \times 7) \times (p \times p \times q)$
$= 28 p^{2} q$

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