Question

Find the product of the following pairs of monomials.

(i) 4, 7p (ii) − 4p, 7p (iii) − 4p, 7pq

(iv) 4p³, − 3p (v) 4p, 0

Answer 1

The product will be as follows.

(i) 4 × 7p = 4 × 7 × p = 28p

(ii) − 4p × 7p = − 4 × p × 7 × p = (− 4 × 7) × (p × p) = − 28 p²

(iii) − 4p × 7pq = − 4 × p × 7 × p × q = (− 4 × 7) × (p × p × q) = − 28p²q

(iv) 4p³ × − 3p = 4 × (− 3) × p × p × p × p = − 12 p⁴

(v) 4p × 0 = 4 × p × 0 = 0