Find the product of the terms.
$3 x^{2} y, - 3 x y^{3}, x^{2} y^{2}$

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Solution

$(3 x^{2} y) \times (- 3 x y^{3}) \times (x^{2} y^{2})$

$= (+) \times (-) \times (+) \times (3 \times 3 \times 1) (x^{2} \times x \times x^{2}) \times (y \times y^{3} \times y^{2})$

$= - 9 x^{5} y^{6}$

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