Find the product of $x, x^{2}, x^{3}, x^{4}$

x^{11}

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x^{8}

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x^{9}

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x^{10}

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Solution

The correct option is C $x^{10}$
The exponent or product rule states that while multiplying two powers having the same base, we have to add the exponents.
$\Rightarrow x \times x^{2} \times x^{3} \times x^{4}$
$\Rightarrow x^{1 + 2 + 3 + 4}$
$\Rightarrow x^{10}$

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Similar questions

Q. The remainder when the polynomial

1 + x^{2} + x^{4} + x^{6} + \dots . + x^{22}

is divided by

1 + x + x^{2} + x^{3} + \dots . + x^{11}

Find the coefficient of $x^{15}$ in $(x^{3} + x^{6} + x^{9} + . . . . . . . . . . .) (x^{2} + x^{4} + x^{6} + . . . . . . . . . . .) (x + x^{2} + x^{3} + . . . . . . . . . .)$

Q. Let

x_{1}, x_{2}, . . . . . x_{n}

be in an AP of

x_{1} + x_{4} + x_{9} + x_{11} + x_{20} + x_{22} + x_{27} + x_{30} = 272

, then

x_{1} + x_{2} + x_{3} + . . . . . + x_{30}

is equal to

Q. Let

x_{1}, x_{2}, . . . . ., x_{n}

be in an AP. If

x_{1} + x_{4} + x_{9} + x_{11} + x_{20} + x_{22} + x_{27} + x_{30} = 272

, then

x_{1} + x_{2} + x_{3} + . . . . + x_{30}

is equal to

x_{1}, x_{2}, x_{3}, . . . .

are in A.P.
If

x_{1} + x_{7} + x_{10} = - 6

and

x_{3} + x_{8} + x_{12} = - 11

, then

x_{3} + x_{8} + x_{22} = ?

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Find the product of x,x2,x3,x4

The correct option is C x10The exponent or product rule states that while multiplying two powers having the same base, we have to add the exponents.⇒x×x2×x3×x4⇒x1+2+3+4⇒x10

Find the product of $x, x^{2}, x^{3}, x^{4}$

The correct option is C $x^{10}$
The exponent or product rule states that while multiplying two powers having the same base, we have to add the exponents.
$\Rightarrow x \times x^{2} \times x^{3} \times x^{4}$
$\Rightarrow x^{1 + 2 + 3 + 4}$
$\Rightarrow x^{10}$