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Expansion of (x^2 - y^2)

Find the prod...

Question

Find the product $(y - 4) (y + 4)$

y - 4

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y^{2} - 4

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y - 16

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y^{2} - 16

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Solution

The correct option is D $y^{2} - 16$
$(y - 4) (y + 4)$ , using the formula $(x + y) (x - y) = x^{2} - y^{2}$
$= y^{2} - 4^{2}$
$= y^{2} - 16$

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Similar questions

\frac{x^{2}}{16} - \frac{y^{2}}{25}

(\frac{x}{4} + \frac{y}{5}) (\frac{x}{4} + \frac{y}{5})

\frac{y^{3} - 8}{y^{2} - 4}

y^{2} + 8 y + 16 = 0

y = - 4

x, y

4 x - y = 4; x - 4 y = 16

y^{2} = 16 \sqrt{3} x

2 x^{2} + y^{2} = 4

y = 2 x + 2 \sqrt{3}

y = m x + \frac{4 \sqrt{3}}{m}, (m \neq 0)

y^{2} = 16 \sqrt{3} x

2 x^{2} + y^{2} = 4

m

m^{4} + 2 m^{2} = 24

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