Question

Find the product
1=$\left(a^2\right)\times \left(2a^{22}\right)\times \left(4a^{26}\right)$
2 = $\left(\frac{2}{3}xy\right)\times \left(\frac{-9}{10}{x}^2{y}^2\right)$
3= $\left(-\frac{10}{3}p{q}^3\right)\times \left(\frac{6}{5}{p}^{3}q\right)$
4=$x\times x^2\times x^3\times x^4$

Answer 1

Given

$\left(1\right).\left(a^2\right)\times \left(2a^{22}\right)\times \left(4a^{26}\right)$ $(m^a{m}^b=m^{a+b})$

$=2\times 4\left(a^{2+22+26}\right)$

$=8\left(a^{50}\right)$

$\left(2\right).\frac{2}{3}\left(xy\right)\times$\dfrac{9}{10}{(x^2y^2)$

$=-\frac{3}{5}\left(x^3{y}^3\right)$

$3.(-\frac{10}{3}p{q}^3)\times \left(\frac{6}{5}{p}^{3}q\right)$

$-4\left(p^4{q}^4\right)$

$4.x\times x^2\times x^3\times x^4$

$=x^{1+2+3+4}$

$=x^{10}$.