Question

Find the products:

$\left(\frac{-1}{27}{a}^2{b}^2\right)\times \left(\frac{-9}{2}{a}^{3}b{c}^2\right)$

Answer 1

$$\begin{gathered} =(\frac{-1}{27}\times \frac{-9}{2})\times ({\mathrm{a}}^2\times {\mathrm{a}}^3\times {\mathrm{b}}^2\times \mathrm{b}\times {\mathrm{c}}^2) \\ =\frac{1}{6}\times {\mathrm{a}}^{(2+3)}\times {\mathrm{b}}^{(2+1)}\times {\mathrm{c}}^2 \\ =\frac{1}{6}{\mathrm{a}}^5{\mathrm{b}}^3{\mathrm{c}}^2 \end{gathered}$$