Question

Find the products:

$\left(\frac{-3}{14}x{y}^4\right)\times \left(\frac{7}{6}{x}^{3}y\right)$

Answer 1

$$\begin{gathered} =(\frac{-3}{14}\times \frac{7}{6})\times (\mathrm{x}\times {\mathrm{x}}^3\times {\mathrm{y}}^4\times \mathrm{y}) \\ =\frac{-1}{4}{\mathrm{x}}^{(1+3)}\times {\mathrm{y}}^{(4+1)} \\ =\frac{-1}{4}{\mathrm{x}}^4{\mathrm{y}}^5 \end{gathered}$$