Question

Find the products:

$\left(\frac{4}{3}{x}^{2}yz\right)\times \left(\frac{1}{3}{y}^{2}zx\right)\times \left(-6xy{z}^2\right)$

Answer 1

$$\begin{gathered} =(\frac{4}{3}\times \frac{1}{3}\times (-6\left)\right)\times ({\mathrm{x}}^2\times \mathrm{x}\times \mathrm{x}\times \mathrm{y}\times {\mathrm{y}}^2\times \mathrm{y}\times \mathrm{z}\times \mathrm{z}\times {\mathrm{z}}^2) \\ =\frac{-8}{3}\times {\mathrm{x}}^{(2+1+1)}\times {\mathrm{y}}^{(1+2+1)}\times {\mathrm{z}}^{(1+1+2)} \\ =\frac{-8}{3}{\mathrm{x}}^4{\mathrm{y}}^4{\mathrm{z}}^4 \end{gathered}$$