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Question

Find the projection (vector) of 2^i^j+^k on ^i2^j+^k.


Solution

As projection vector of a on b=(a.^b)^b
So, projection of 2^i^j+^k on ^i2^j+^k is [(2^i^j+^k).(^i2^j+^k12+(2)2+12)](^i2^j+^k12+(2)2+12)
i.e., =[(2^i^j+^k).(^i2^j+^k6)](^i2^j+^k6)=(2+2+16)(^i2^j+^k6)=5(^i2^j+^k)6).

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