Find the proportionality constant of the following table- array - c - c -No- of - days -y - 96 - 72 - 48 - 36832 - 18 1hline lend array A- 328B- 468C- 288D- 108

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Question

Find the proportionality constant of the following table.

$\begin{matrix} N o . o f w o r k e r s (x) & 3 & 4 & 6 & 8 & 9 & 16 N o . o f d a y s (y) & 96 & 72 & 48 & 36 & 32 & 18 \end{matrix}$

108

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328

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468

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288

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Solution

The correct option is D
288

Here, x and y are inversely proportional so, the product of x and y is always constant.

When we take the product of x and y, it is constant.

Here, proportionality constant = $3 \times 96 = 4 \times 72 = 6 \times 48 = 8 \times 36 = 9 \times 32 = 16 \times 18 = 288$

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Find the proportionality constant of the following table. No. of workers (x)3468916No. of days (y)967248363218

The correct option is D 288 Here, x and y are inversely proportional so, the product of x and y is always constant. When we take the product of x and y, it is constant. Here, proportionality constant = 3× 96=4×72=6×48=8×36=9×32=16×18=288

Find the proportionality constant of the following table.

$\begin{matrix} N o . o f w o r k e r s (x) & 3 & 4 & 6 & 8 & 9 & 16 N o . o f d a y s (y) & 96 & 72 & 48 & 36 & 32 & 18 \end{matrix}$

The correct option is D
288

Here, x and y are inversely proportional so, the product of x and y is always constant.

When we take the product of x and y, it is constant.

Here, proportionality constant = $3 \times 96 = 4 \times 72 = 6 \times 48 = 8 \times 36 = 9 \times 32 = 16 \times 18 = 288$