Question

Find the Pythagorean triplet whose one member is $18$.

• A. $28$ and $20$
• B. $80$ and $82$
• C. $72$ and $92$
• D. $34$ and $54$

Answer 1

The correct option is B $80$ and $82$

Using $2m,m^2+1,m^2-1$ forms
Let us take $2m=18$

$m=\frac{18}{2}=9$

if $m=9,m^2-1=9^2=81-1=80$
if $m=9,m^2+1=9^2=81+1=82$
Therefore, B is the correct answer.