Question

Find the Pythagorean triplet whose one number is
(a) $10$
(b) $15$
(c) $50$

Answer 1

$\left(a\right)6^2+8^2={10}^2$

$\therefore Tripletis6,8,10$

$\left(b\right)8^2+{15}^2={17}^2$

$\therefore Tripletis8,15,17$

$\left(c\right){30}^2+{40}^2={50}^2$

$\therefore Tripletis30,40,50$