Question

Find the Q value of the reaction
$N^{14}+\alpha \to O^{17}+p$
The masses of $N^{14},H{e}^4,p,$ and $O^{17}$ are, respectively, 14.00307 u, 4.00260 u, 1.00783 u, and 16.99913 u. Find the total kinetic energy of the products if the striking $\alpha -$ particle has the minimum kinetic energy required to initiate the reaction:

Answer 1

$N^{14}+\alpha \to O^{17}+p$

Energy = E = $△m{c}^2$

$△m=14.00307+4.00260-1.00783-16.99913=-0.00129E=△m{c}^2=-0.00129\times 931MeV=-1.20099MeV$

So, 1.20099 MeV energy is required to initiate the reaction.