Question

Find the Quadratic Equation whose roots are Reciprocal of $a{x}^2+bx+c=0$.

• A. $a{x}^2+bx+c=0$
• B. $a(\frac{1}{x}{)}^2+b(\frac{1}{x})+c=0$
• C. $3a{x}^2+2bx+c=0$
• D. None of the above

Answer 1

The correct option is B $a(\frac{1}{x}{)}^2+b(\frac{1}{x})+c=0$

We know that for reciprocal roots, we only need to replace $x$ by $\frac{1}{x}$, in the given equation.
So the above equation becomes:
$a(\frac{1}{x}{)}^2+b(\frac{1}{x})+c=0$, which is the required answer.