Question

Find the quadratic equation, whose roots are tripple of the roots of the equation $3a{x}^2+3bx+c=0$.

Answer 1

Given the quadratic equation is $3a{x}^2+3bx+c=0$.......(1).

Now we are to find the equation whose roots are tripple of the roots of the equation (1).

So the equation will be obtained by replacing $x$ by $\frac{x}{3}$ in (1) we get,

$3a\frac{x^2}{9}+3b\frac{x}{3}+c=0$

or, $a{x}^2+3bx+3c=0$.