Question

Find the quadratic equation whose solution set is (2, -3)

• A. (x + a) (x – 2a)
• B. (x – 2a) (x + 2a)
• C. (x + a) (x + 2a)
• D. (x – a) (x – a)

Answer 1

The correct option is A

(x + a) (x – 2a)

If the roots of the equation are 2 and -3 , then $x=2$ or $x=-3$

$\Rightarrow$ $x-2$$x+3=0$

$\Rightarrow$ $x^2-2x+3x-6=0$

$\Rightarrow$ $x^2+x-6=0$