Find the quadratic polynomial whose sum & product of the zeroes r 21/8 & 5/16 respectively.Thanks

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Solution

Let the zeroes be à and ß

Sum of zeroes = 21/8

=> à + ß = 21/8

Product of zeroes = 5/16

=> as = 5/16

The required quadratic polynomial is

→ k {x² - (à+ß)x + aß}

→ k {x² - (21/8)x+5/16}

→ k {x²-42x/16 + 5/16}

Put k = 16

→ 16x²-42x+5

R

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Q. Question 1 (ii)
For each of the following, find a quadratic polynomial whose sum and product of the zeroes respectively are as given. Also, find the zeroes of these polynomials by factorization.
ii)

\frac{21}{8}, \frac{5}{16}

For each of the following, find a quadratic polynomial whose sum and product respectively of the zeroes are as given. Also, find the zeroes of these polynomials by factorization.

(i) $- \frac{8}{3}, \frac{4}{3}$ (ii) $\frac{21}{8}, \frac{5}{16}$ (iii) $- 2 \sqrt{3}, - 9$ (iv) $\frac{- 3}{2 \sqrt{5}}, - \frac{1}{2}$

Find the quadratic polynomial whose sum of its zeroes (roots) is $- \frac{8}{5}$ and the product of the zeroes (roots) is $\frac{7}{5}$ .

Find the quadratic polynomial, sum of whose zeros is $8$ and their product is $12$ . Hence, find the zeros of the polynomial.

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Find the quadratic polynomial whose sum & product of the zeroes r 21/8 & 5/16 respectively.Thanks

Let the zeroes be à and ß Sum of zeroes = 21/8 => à + ß = 21/8 Product of zeroes = 5/16 => as = 5/16 The required quadratic polynomial is → k {x² - (à+ß)x + aß} → k {x² - (21/8)x+5/16} → k {x²-42x/16 + 5/16} Put k = 16 → 16x²-42x+5 R

Let the zeroes be à and ß

Sum of zeroes = 21/8

=> à + ß = 21/8

Product of zeroes = 5/16

=> as = 5/16

The required quadratic polynomial is

→ k {x² - (à+ß)x + aß}

→ k {x² - (21/8)x+5/16}

→ k {x²-42x/16 + 5/16}

Put k = 16

→ 16x²-42x+5

R