Find the quadratic polynomial whose zeroes are 6+√33 and 6−√33 .
3x2−12x+11
Let α & β be the roots.
Sum of zeroes, α+β=6+√33+6−√33 =123=4
Product of zeroes, αβ=6+√33×6−√33=62−(√3)29αβ=36−39=339=113
Required polynomial f(x)=[(x2−(α+β)x+(αβ)] =[(x2−4x+113]
Multiplying by 3
⇒f(x)=3x2−12x+11
∴ the required polynomial is 3x2−12x+11.