Find the quartile deviation of 6, 12,14, 16, 18, 20 and 24.

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Solution

The ascending order of the given observations is 6, 12, 14, 16, 18, 20, 24
$Q_{1} = {(\frac{n + 1}{4})}^{t h}$ observation = 2nd observation = 12
$Q_{3} = 3 {(\frac{n + 1}{4})}^{t h}$ observation = 6 th observation = 20
$Q . D . = \frac{Q_{3} - Q_{1}}{2} = \frac{20 - 12}{2} = 4$

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Find the quartile deviation of 6, 12,14, 16, 18, 20 and 24.

The ascending order of the given observations is 6, 12, 14, 16, 18, 20, 24Q1=(n+14)th observation = 2nd observation = 12Q3=3(n+14)th observation = 6 th observation = 20Q.D.=Q3−Q12=20−122=4

The ascending order of the given observations is 6, 12, 14, 16, 18, 20, 24
$Q_{1} = {(\frac{n + 1}{4})}^{t h}$ observation = 2nd observation = 12
$Q_{3} = 3 {(\frac{n + 1}{4})}^{t h}$ observation = 6 th observation = 20
$Q . D . = \frac{Q_{3} - Q_{1}}{2} = \frac{20 - 12}{2} = 4$