Question

Find the quotient : $4m^4{n}^4–8m^3{n}^4+6m{n}^3$ by -2mn

• A. $2m^3{n}^3-4m^2{n}^3+3n^2$
• B. $-2m^2{n}^3+4m^3{n}^2-3mn2$
• C. $-2m^3{n}^3+4m^2{n}^3-3n^2$
• D. $-2m^3{n}^3+4m^2{n}^3-3n^2$

Answer 1

The correct option is C $-2m^3{n}^3+4m^2{n}^3-3n^2$

$=(4m^4{n}^4–8m^3{n}^4+6m{n}^3)÷-2mn$
= $\frac{4m^4{n}^4}{-2mn}-\frac{8m^3{n}^4}{-2mn}+\frac{6m{n}^3}{-2mn}$
Now, each term is simplified by cancelling out the common factors.
$=-2m^3{n}^3+4m^2{n}^3-3n^2$