Question

Find the quotient: $(-9y^6)÷\left(9y^2\right)$

Answer 1

Divide ${-9y}^6$ by $9y^2$ as follows:

$\frac{{-9y}^6}{9y^2}=\frac{-9}{9}(y^6\times y^{-2})=-1\left(y^{6-2}\right)=-y^4(\because \frac{1}{a^m}=a^{-m},a^x\times a^y=a^{x+y})$

Hence, $\frac{{-9y}^6}{9y^2}=-y^4$