Find the Quotient and the Remainder when the first polynomial is divided by the second.
$(2 x^{3} - 5 x^{2} + 8 x - 5)$ by $(2 x^{2} - 3 x + 5)$

Quotient

= x + 1

, Remainder

= 0

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Quotient

= x - 1

, Remainder

= 0

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Quotient

= x - 1

, Remainder

= 1

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Quotient

= - x - 1

, Remainder

= 0

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Solution

The correct option is A Quotient $= x - 1$ , Remainder $= 0$
Quotient = $x - 1$ , remainder = $0$

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