Question

Find the quotient:$\frac{30k^9}{6k^2}$

Answer 1

Divide $30k^9$ by $6k^2$ as follows:

$\frac{30k^9}{6k^2}=\frac{30}{6}(k^9\times k^{-2})=5\left(k^{9-2}\right)=5k^7(\because \frac{1}{a^2}=a^{-2},a^x\times a^y=a^{x+y})$

Hence, $\frac{30k^9}{6k^2}=5k^7$