Find the quotient the and remainder of the following division:
$(4 x^{3} - 2 x^{2} + 6 x + 7) \div (3 + 2 x)$

Open in App

Solution

Steps:
1) Multiply $(2 x + 3)$ with $2 x^{2}$ , to get $4 x^{3}$ , remainder $= - 8 x^{2} + 6 x$
2) Multiply $(2 x + 3)$ with $- 4 x$ , to get $- 8 x^{2}$ , remainder $= 18 x + 7$
3) Multiply $(2 x + 3)$ with $9$ , to get $18 x + 7$ , remainder $= - 20$
Quotient $= 2 x^{2} - 4 x + 9$ , Remainder $= - 20$

Suggest Corrections

Similar questions

(8 x^{4} - 2 x^{2} + 6 x - 7)

(2 x + 1)

(4 x^{3} + p x^{2} - q x + 3)

p, q

(2 x^{2} - 3 x - 14) \div (x + 2)

(8 x^{4} - 2 x^{2} + 6 x - 5) \div (4 x + 1)

4 x^{3} + x^{2} - 2 x + 3

x + 2

8 x^{4} - 2 x^{2} + 6 x - 7

2 x + 1

4 x^{3} + p x^{2} - q x + 3

q - p

Join BYJU'S Learning Program